You are given an array prices where prices[i] is the price of a given stock on the ith day.

Find the maximum profit you can achieve. You may complete at most two transactions.

Note: You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).


Test Cases

Input:

(int[]) prices = [3,3,5,0,0,3,1,4]

Output:

(int) 6

Explanation:

Buy on day 4 (price = 0) and sell on day 6 (price = 3), profit = 3-0 = 3.
Then buy on day 7 (price = 1) and sell on day 8 (price = 4), profit = 4-1 = 3.

Input:

(int[]) prices = [1,2,3,4,5]

Output:

(int) 4

Explanation:

Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
Note that you cannot buy on day 1, buy on day 2 and sell them later, 
as you are engaging multiple transactions at the same time. You must sell before buying again.

Input:

(int[]) prices = [7,6,4,3,1]

Output:

(int) 0

Explanation:

In this case, no transaction is done, i.e. max profit = 0.

Solution

class Solution {
public:
    int maxProfit(vector<int>& prices) {
        int oneBuy = INT_MIN, oneBuyOneSell = 0;
        int twoBuy = INT_MIN, twoBuyTwoSell = 0;
        for(int i=0; i<prices.size(); i++) {
            oneBuy = max(oneBuy, -prices[i]);
            oneBuyOneSell = max(oneBuyOneSell, oneBuy + prices[i]);
            twoBuy = max(twoBuy, oneBuyOneSell -prices[i]);
            twoBuyTwoSell = max(twoBuyTwoSell, twoBuy + prices[i]);
        }
        return max(oneBuyOneSell, twoBuyTwoSell);
    }
};
import java.util.*;

class Solution {
    public int maxProfit(int[] prices) {
        int oneBuy = Integer.MIN_VALUE, oneBuyOneSell = 0;
        int twoBuy = Integer.MIN_VALUE, twoBuyTwoSell = 0;
        for(int i=0; i<prices.length; i++) {
            oneBuy = Math.max(oneBuy, -prices[i]);
            oneBuyOneSell = Math.max(oneBuyOneSell, oneBuy + prices[i]);
            twoBuy = Math.max(twoBuy, oneBuyOneSell -prices[i]);
            twoBuyTwoSell = Math.max(twoBuyTwoSell, twoBuy + prices[i]);
        }
        return Math.max(oneBuyOneSell, twoBuyTwoSell);
    }

    public static void main(String[] args) {
        Solution solution = new Solution();
        int[] prices = new int[]{3,3,5,0,0,3,1,4};
        System.out.println(solution.maxProfit(prices));
    }
}
from typing import List


class Solution:
    def maxProfit(self, prices: List[int]) -> int:
        ob, tb = float('-inf'), float('-inf')
        obos, tbts = 0, 0
        for price in prices:
            ob = max(ob, -price)
            obos = max(obos, ob + price)
            tb = max(tb, obos - price)
            tbts = max(tbts, tb + price)
        return max(obos, tbts)


if __name__ == '__main__':
    prices = [3, 3, 5, 0, 0, 3, 1, 4]
    solution = Solution()
    print(solution.maxProfit(prices))
Time Complexity: O(n)
Space Complexity: O(1)